70/3.14=r^2

Solution for 70/3.14=r^2 equation:

70/3.14=r^2

We move all terms to the left:

70/3.14-(r^2)=0

We add all the numbers together, and all the variables

-1r^2+70/3.14=0

We multiply all the terms by the denominator


-1r^2*3.14+70=0

Wy multiply elements

-3.14r^2+70=0

a = -3.14; b = 0; c = +70;
Δ = b2-4ac
Δ = 02-4·(-3.14)·70
Δ = 879.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{879.2}}{2*-3.14}=\frac{0-\sqrt{879.2}}{-6.28}
=-\frac{\sqrt{}}{-6.28}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{879.2}}{2*-3.14}=\frac{0+\sqrt{879.2}}{-6.28}
=\frac{\sqrt{}}{-6.28}
$